12x^2-28x+12=)

Solution for 12x^2-28x+12=) equation:

12x^2-28x+12=)

We move all terms to the left:

12x^2-28x+12-())=0

We add all the numbers together, and all the variables

12x^2-28x=0

a = 12; b = -28; c = 0;
Δ = b2-4ac
Δ = -282-4·12·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28}{2*12}=\frac{0}{24}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28}{2*12}=\frac{56}{24}
=2+1/3
$